Talk:CPAR voting

Add topic
There are no discussions on this page.


15: A>B 7:A 33: B>A 6: C>B 38: C 34: ABC (or >ABC, or mixed between X>ABC and Y>ABC)

Note that this is not far from being a Condorcet cycle, C>B>A>C, but actually B>C barely.

In particular, the "cyclicness" is more than half the B>A margin. Which I think is the basic fact that must be true for FBC to be violated. Which means that while candidate A is the one to benefit from the lack of favorite betrayal, factions B and C must stand in an asymmetrical (quasi-cyclic) relationship in order for this to happen. There's no way faction A could engineer this situation; they could only at best try to take advantage in the rare cases that it happened to obtain (and they knew that it did with enough precision).

Return to "CPAR voting" page.