# Talk:Majority Defeat Disqualification Approval

Revision as of 20:34, 25 October 2005 by imported>KVenzke

Douglas Woodall gives this example to show that MDDA fails Plurality:

20 ab 5 ba 24 bc 24 ca 9 dab 9 dbc 9 dca a,b,c are preferred to d by 49,49,48 voters respectively, which are not majorities, but a>b by 62, b>c by 67 and c>a by 66, so that a, b and c are all disqualified. Thus MDDA elects d. But d has 27 votes in total, and so is debarred by b who has 29 first-preference votes.

Kevin Venzke 13:34, 25 Oct 2005 (PDT)