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== Examples ==
5winner example, Hare quota 50 (example done using scored ballots):
{ class="wikitable"
!Number
A1:0 A2:0 A3:0 A4:0 A5:0 B1:0 C1:0 D1:0 E1:0 F1:10
}
Looking at the top 5 lines, 50 voters, a Hare quota, mutually most prefer the set of candidates (A15) over all other candidates, so HarePSC requires at least one of (A15) must win. (Note that Sequential Monroe voting fails HarePSC in this example. However, one could forcibly make SMV do so by declaring that the candidate with the highest Monroe score within the set (A15) must win the first seat, for example.) <ref>https://forum.electionscience.org/t/anexampleofmaximaldivergencebetweensmvandharepsc/586</ref>
Generally, DroopPSC makes it more likely that a majority will win at least half the seats than only HarePSC. The reason for this is that majority solid coalitions always constitute enough Drool quotas to always win at least half the seats, while with Hare quotas they can only guarantee they will win just under half the seats and have over half a Hare quota to win the additional seat required to get at least half the seats. 5winner example using STV with Hare quotas:
{ class="wikitable"
!Number
B3>B2>B1>A1>A3>A2
}
Note that 51 voters, a majority, prefer (A13) over all other candidates, and thus electing all 3 of them would mean 3 out of 5 seats, a majority, would belong to the majority. Also, the Droop quota here is 17, and thus by DroopPSC the majority has 51/17=3 PR guarantees, which would give them a majority of seats. However, by HarePSC, they only have 51/20 rounded down = 2 PR guarantees, and thus by HareSTV:
▲<br /><blockquote>So, the Hare quota here is 20. A1 and A2 are immediately elected, but posttransfer A3 only has 11 votes, and is thus eliminated first. B1, B2, B3 take the remaining 3 seats.<ref>https://www.reddit.com/r/EndFPTP/comments/ermb1s/comment/ff7a7f8</ref></blockquote>
There can be quota overlaps when assigning PSC claims; suppose a group constituting 80% of a quota of voters vote A>B>C>D, another group of 80% of a quota vote B>A>C>D, and another group of 50% of a quota vote C>A=B=D. Then, 2 candidates must be elected from the set (A, B, C, D), since in total 2.1 quotas mutually most prefer that set, but a further constraint is that 1 candidate must win from within (A, B), since 1.6 quotas mutually most prefer them. It would not satisfy PSC if the final winner set had neither A or B in it in other words, even if it had C and D.
== Generalised solid coalitions ==
The Expanding Approvals Rule passes a stricter PR axiom than PSC:
The Expanding Approvals Rule passes a stricter PR axiom than PSC:<blockquote>Definition 5 (Generalised solid coalition) A set of voters N′ is a generalised solid coalition for a set of candidates C′ if every voter in N′ weakly prefers every candidate in C′ at least as high as every candidate in C\C′. That is, for all i ∈ N′ and for any c′ ∈ C′▼
▲
: ∀c ∈ C\C′ c′ i c.
to solid coalition. Let c(i, j) denotes voter i’s jth most preferred candidate. In case the voter’s preference has indifferences, we use lexicographic tiebreaking to identify the candidate in the jth position.▼
▲We note that under strict preferences, a generalised solid coalition is equivalent to solid coalition. Let c(i, j) denotes voter i’s jth most preferred candidate. In case the voter’s preference has indifferences, we use lexicographic tiebreaking to identify the candidate in the jth position.
Definition 6 (Generalised qPSC) Let q ∈ (n/(k + 1), n/k]. A committee W satisfies generalised qPSC if for all generalised solid coalitions N′ supporting candidate subset C′ with size N′ ≥ ℓq, there exists a set C′′ ⊆ W with size at least min{ℓ, C′} such that for all c′′ ∈ C′′▼
▲'''Definition 6 (Generalised qPSC)''' Let q ∈ (n/(k + 1), n/k]. A committee W satisfies generalised qPSC if for all generalised solid coalitions N′ supporting candidate subset C′ with size N′ ≥ ℓq, there exists a set C′′ ⊆ W with size at least min{ℓ, C′} such that for all c′′ ∈ C′′
∃i ∈ N′ : c′′ i c(i,C′ ). The idea behind generalised qPSC is identical to that of qPSC and in fact generalised qPSC is equivalent to qPSC under linear preferences. Note that in the definition above, a voter i in the solid coalition of voters N′ does not demand membership of candidates from the solidly supported subset C′ but of any candidate that is at least as preferred as a least preferred candidate in C′. Generalised weak qPSC is a natural weakening of generalised qPSC in which we require that C′ is of size at most ℓ.▼
: ∃i ∈ N′ : c′′ i c(i,C′ ).
Definition 7 (Generalised weak qPSC) Let q ∈ (n/(k + 1), n/k]. A committee W satisfies weak generalised qPSC if for every positive integer ℓ, and every generalised solid coalition N′ supporting a candidate subset C′▼
▲
▲'''Definition 7 (Generalised weak qPSC)''' Let q ∈ (n/(k + 1), n/k]. A committee W satisfies weak generalised qPSC if for every positive integer ℓ, and every generalised solid coalition N′ supporting a candidate subset C′
: C′ ≤ ℓ with size N′ ≥ ℓq, there
exists a set C′′ ⊆ W with size at least min{ℓ, C′} such that for all c′′ ∈ C′′
: ∃i ∈ N′ : c′′ i c(i,C′ ).<ref>https://arxiv.org/abs/1708.07580 p. 8</ref></blockquote
== Notes ==
DroopPSC implies HarePSC, since a Hare quota is simply a large Droop quota, but the same doesn't hold the other way around. HarePSC is equivalent to the unanimity criterion and DroopPSC to the mutual majority criterion in the singlewinner case. Note that this means cardinal PR methods can only pass HarePSC and not DroopPSC in order to reduce to cardinal methods that fail the mutual majority criterion in the singlewinner case, which is most of them.
Note that PSC doesn't hold if some voters in a coalition back outofcoalition candidates i.e. 1winner example with Droop quota of 51:
<blockquote>26 A>B
25 B
49 C</blockquote>
49 C</blockquote>STV would elect C here. Yet if A hadn't run, then B would've been 51 voter's 1st choice, so a Droop solid coalition would've been backing them, and since STV passes DroopPSC, B would've guaranteeably won. ▼
▲
One could also consider various extensions of the solid coalition idea, in part to address examples like the above one; 5winner example:
9 B>F>G>H>I>J
8 K
7 L</blockquote>
7 L</blockquote>Arguably there is some kind of coalition of 45 voters backing candidates A through J here, and since the largest opposing coalition is 8 voters, D'Hondt would say that the 45voter coalition ought to win all 5 seats. At that point, one could eliminate all candidates outside the 45voter coalition (K and L) at which point A through E all are a Hare quota's 1st choice and must all win. This sort of thinking is generally what Condorcet PR methods such as Schulze STV do. ▼
▲
