User:BetterVotingAdvocacy/Big page of ideas: Difference between revisions
User:BetterVotingAdvocacy/Big page of ideas (view source)
Revision as of 01:01, 7 July 2020
, 3 years ago→Score voting
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One way to understand a voter's absolute score for a candidate is that they are expressing their degree of support for that candidate pairwise against a candidate they don't support at all.
The expressiveness of a rated ballot, as measured by "number of possible votes (permutations) a voter can submit", is greatly reduced if removing non-normalized votes from contention (i.e. on the grounds that they reduce voter power). For example, with a scale of 0 to 3 and 3 candidates, there are 4^3=64 possible votes<!-- This is derived as follows: pretend there are infinite candidates in the election. When there is only 1 candidate in the election, we can pretend everyone except that 1 candidate is scored the same no matter what (let's say they are all scored at the min score, which is usually 0, for this example), and that that 1 candidate can be scored [number of scores in the scale] ways. So with 1 candidate and a scale of 0 to 4, there are 4 possibilities. With 2 candidates, the 2nd candidate is scored a 0 for every possible score the 1st candidate is scored at. But the 2nd candidate could also be scored a 1 for every possible score the 1st candidate is scored at, etc. So the result is 4*4=16 possibilities. For 3 candidates, there are 4 possible scores the 3rd candidate could be at when the first 2 candidates are moving through all of their possible scores, so that is 4*4*4 or 4^3=64 possibilities. -->, but when removing non-normalized votes, there are only 18 possible votes.<ref>https://forum.electionscience.org/t/different-ways-of-measuring-expressiveness-for-rated-type-ballots/712 There are 20 votes ignored in that analysis, so that's 20 + 26 = 46 non-normalized votes total to ignore.</ref> <!-- (This is because a normalized vote requires one candidate to be at the max score and one candidate to be at the min score, so there are only 4 possibilities for how the 3rd candidate can be scored.)
A:3 B:2 C:0 (=2*3=6, since you could swap B and C here, and you can also swap B or C for A)
A:3 B:1 C:0 (=2*3=6)
A:3 B:0 C:0 (=3, since you can't swap B and C here)
A:3 B:3 C:0 (=3) -->
== Miscellaneous ==
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