Ranked Robin: Difference between revisions

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'''2<sup>nd</sup> Degree:''' For each tied finalist, subtract the number of ballots on which they lost to each other candidate (including candidates who are not finalists) from the number of ballots on which they beat each other candidate (including candidates who are not finalists). The tied finalist with the greatest total difference is elected.
 
'''3<sup>rd</sup> Degree:''' It is highly unlikely that there will still be a tie after the '''2<sup>nd</sup> Degree''' tiebreaker, but if there is, it is not recommended to use tie-breaking methods beyond the '''2<sup>nd</sup> Degree''' tiebreaker for government elections as voter trust may be shaken more by using the '''3<sup>rd</sup> Degree''' tiebreaker and beyond than drawing lots or hosting another election. In the event that there is a tie after the '''Level 2<sup>nd</sup> Degree''' tiebreaker, the differences for the tied candidates will be the same, but the values used to calculate them will likely be different. Elect the tied candidate whose values are closest to the tied differences. For example, if <math display="inline">A</math>, <math display="inline">B
</math>, and <math display="inline">C</math> are tied after the '''2<sup>nd</sup> Degree''' tiebreaker, then <math>A_w-A_l=B_w-B_l=C_w-C_l</math> (where wins and loses are calculated across the entire field of candidates), but it's likely that <math>A_w\neq B_w\neq C_w</math> (and by proxy that <math>A_l\neq B_l\neq C_l</math>). The tied candidate with the greatest loss margin will also have the greatest win margin, and the tied candidate with the least loss margin will have the least win margin. Elect the tied candidate with the least loss and win margins as that is the least polarizing tied candidate.
 
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