Sequential proportional approval voting: Difference between revisions

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The system disadvantages minority groups who share some preferences with the majority. In terms of [[tactical voting]], it is therefore desirable to [[Free riding free ride]] by withholding approval from candidates who are likely to be elected in any case. With the standard [[Jefferson method]] based reweighing it favours large factions in an attempt to mitigate [[Free_riding#Vote_Management | vote management]]. On the other hand [[D'Hondt method]] based reweighting is more fair to smaller factions.
 
It is however a much computationally simpler algorithm than (and can be considered a sequential form of) [[proportional approval voting]], permitting votes to be counted either by hand or by computer, rather than requiring a computer to determine the outcome of all but the simplest elections.<ref name="AzizGaspers2014">{{cite book |last1=Aziz |first1=Haris |author2=Serge Gaspers, Joachim Gudmundsson, Simon Mackenzie, Nicholas Mattei, Toby Walsh |title=Proceedings of the 2015 International Conference on Autonomous Agents and Multiagent Systems |chapter=Computational Aspects of Multi-Winner Approval Voting |chapterurl=https://arxiv.org/pdf/1407.3247v1.pdf |pages=107–115 |isbn=978-1-4503-3413-6}}</ref>
 
== Notes ==
SPAV's [[Party list case|party list case]] is [[D'Hondt]], because its reweighting is based on D'Hondt's divisors.
 
In the same way that [[Approval voting]] is considered by almost nobody to be worse than [[FPTP]], though some question the magnitude of the improvement, many find SPAV to be unambiguously better than [[SNTV]]. This is because it satisfies a stronger [[Weak forms of PSC|weak form of PSC]], which allows solid coalitions to gain proportional representation with less need for coordinated strategy. This makes it less likely to result in anomalous results (i.e. less likely that a minority wins a majority of seats using [[Vote management|vote management]], for example). If every voter bullet votes, SPAV becomes SNTV.
 
==See also==