Anonymous user
Talk:Condorcet method: Difference between revisions
→Self referential condorcet method
Line 13:
::Voter 3: Give score of 4 to A, 10 to B and 5 to C
::C beats both A and B and is the normal condorcet winner, but loses the election to B: ((10+7+7)/3)=8 VS ((8+8+5)/3)=7
::Under Self referential Condorcet Criterion each pairwise competition is made using the voting system being used (at this case range voting) so, B vs A is (10+7+7/3=8) VS (1+10+4/3=5) and B is the winner, B vs C is (10+7+7/3=8) VS (8+8+5/3=7) and here B is the winner to, and so he is the self referential condorcet winner, and the self referential condorcet winner, won the election, but the normal condorcet winner
::: Ah, I think I understand. So "Given a voting method, if the winner of that voting method would beat every other candidate in head-to-head elections ''using that same voting method for the head-to-head elections''"? — [[User:Psephomancy|Psephomancy]] ([[User talk:Psephomancy|talk]]) 15:28, 18 September 2019 (UTC)
::::YES, "Given a voting method, if the winner of that voting method would beat every other candidate in head-to-head elections ''using that same voting method for the head-to-head elections'' he should be the one that would win the election"?
| |||