User:BetterVotingAdvocacy/Negative vote-counting approach for pairwise counting: Difference between revisions

Content added Content deleted
Line 13:
 
# Math: The final number of votes for the first candidate against the second candidate in each head-to-head matchup is then found by, if treating the second value as a positive number, subtracting the second value for the first candidate from the first value (addition is done instead of subtraction if the second value is treated as a negative number).
#* This can be succinctly summarized as, for finding the vote totals in a matchup between candidates A and B:<blockquote>A>=B = A - A<B</blockquote>meaning that the number of ballots ranking A over (or (explicitly) equal to) B, is equal to the number of ballots ranking A, minus the number of ballots ranking A below B (i.e. B over A).
 
 
 
Line 24 ⟶ 23:
 
== Example ==
If the votes are:<blockquote>10: A>B
 
5: B </blockquote>then each candidate is explicitly marked on:
 
* A: 10 ballots
Line 60 ⟶ 59:
 
This can change who wins in certain [[:Category:Pairwise counting-based voting methods|Category:Pairwise counting-based voting methods]]; for example, in the [[Winning votes|winning-votes]] version of a [[:Category:Defeat-dropping Condorcet methods|Category:Defeat-dropping Condorcet method]], not only does it matter who wins the matchup, but also exactly how many voters genuinely preferred the winner to the loser in each matchup.
 
Note: Voters who don't rank either of the candidates in a matchup are generally considered to equally rank them, but no implementation of negative counting would consider them to vote for both candidates in the matchup. Only voters who have marked both candidates can be counted that way.
 
=== Example of the two approaches to equal-ranking ===