Talk:Condorcet method: Difference between revisions

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::Voter 2: Give score of 10 to A, 7 to B and 8 to C
::Voter 2: Give score of 10 to A, 7 to B and 8 to C
::Voter 3: Give score of 4 to A, 10 to B and 5 to C
::Voter 3: Give score of 4 to A, 10 to B and 5 to C
::C beats both A and B and is the normal condorcet winner, but loses the election to B ((10+7+7)/3)=8 VS ((8+8+5)/3)=7
::C beats both A and B and is the normal condorcet winner, but loses the election to B: ((10+7+7)/3)=8 VS ((8+8+5)/3)=7
::Under Self referential Condorcet Criterion each pairwise competition is made using the voting system being used (at this case range voting) so, B vs A is (10+7+7/3=8) VS (1+10+4/3=5) and B is the winner, B vs C is (10+7+7/3=8) VS (8+8+5/3=7) and here B is the winner to, and so he is the self referential condorcet winner, and the self referential condorcet winner, won the election, but the normal condorcet winner didnt.[[Special:Contributions/177.92.128.62|177.92.128.62]] 13:29, 18 September 2019 (UTC)
::Under Self referential Condorcet Criterion each pairwise competition is made using the voting system being used (at this case range voting) so, B vs A is (10+7+7/3=8) VS (1+10+4/3=5) and B is the winner, B vs C is (10+7+7/3=8) VS (8+8+5/3=7) and here B is the winner to, and so he is the self referential condorcet winner, and the self referential condorcet winner, won the election, but the normal condorcet winner didnt.[[Special:Contributions/177.92.128.62|177.92.128.62]] 13:29, 18 September 2019 (UTC)
::: Ah, I think I understand. So "Given a voting method, if the winner of that voting method would beat every other candidate in head-to-head elections ''using that same voting method for the head-to-head elections''"? — [[User:Psephomancy|Psephomancy]] ([[User talk:Psephomancy|talk]]) 15:28, 18 September 2019 (UTC)
::: Ah, I think I understand. So "Given a voting method, if the winner of that voting method would beat every other candidate in head-to-head elections ''using that same voting method for the head-to-head elections''"? — [[User:Psephomancy|Psephomancy]] ([[User talk:Psephomancy|talk]]) 15:28, 18 September 2019 (UTC)

Revision as of 18:50, 18 September 2019

Another possible acronym for condorcet methods is Virtual One-on-one Tournament Elections - VOTE. Homunq 15:07, 28 August 2009 (UTC)


Self referential condorcet method

The article "One which always elects the pairwise champion if such exists", the thing is the parwise competition is made with first part the post (or something similar to approval system if you allow equal rankings).

Couldn't you have some sort of self referential Condorcet method, where you check if someone won the pairwise competition, using the voting method you are testing to check if it's a condorcet method or not? Range voting as some example would pass this self referential condorcet method (also range vote is better than first past the post even with just two candidates).

User:177.92.128.62 Can you give an example? This is hard to follow. — Psephomancy (talk) 04:16, 9 June 2019 (UTC)
1-10 Range voting and 3 candidates, A, B and C and 3 voters 1, 2 and 3:
Voter 1: Give score of 1 to A, 7 to B and 8 to C
Voter 2: Give score of 10 to A, 7 to B and 8 to C
Voter 3: Give score of 4 to A, 10 to B and 5 to C
C beats both A and B and is the normal condorcet winner, but loses the election to B: ((10+7+7)/3)=8 VS ((8+8+5)/3)=7
Under Self referential Condorcet Criterion each pairwise competition is made using the voting system being used (at this case range voting) so, B vs A is (10+7+7/3=8) VS (1+10+4/3=5) and B is the winner, B vs C is (10+7+7/3=8) VS (8+8+5/3=7) and here B is the winner to, and so he is the self referential condorcet winner, and the self referential condorcet winner, won the election, but the normal condorcet winner didnt.177.92.128.62 13:29, 18 September 2019 (UTC)
Ah, I think I understand. So "Given a voting method, if the winner of that voting method would beat every other candidate in head-to-head elections using that same voting method for the head-to-head elections"? — Psephomancy (talk) 15:28, 18 September 2019 (UTC)
YES, "Given a voting method, if the winner of that voting method would beat every other candidate in head-to-head elections using that same voting method for the head-to-head elections he should be the one that would win the election"?