Talk:Ranked Robin: Difference between revisions

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: I seem to recall that this method is Copeland//Borda, whereas Black is Condorcet//Borda (or Condorcet,Borda; those are the same because there's only one CW). If I'm right, then that should probably be pointed out in the article. It lacks a quick summary of just what kind of method it is, like the first sentence of [[Black's method]]. [[User:Kristomun|Kristomun]] ([[User talk:Kristomun|talk]]) 00:06, 23 November 2021 (UTC)
: I seem to recall that this method is Copeland//Borda, whereas Black is Condorcet//Borda (or Condorcet,Borda; those are the same because there's only one CW). If I'm right, then that should probably be pointed out in the article. It lacks a quick summary of just what kind of method it is, like the first sentence of [[Black's method]]. [[User:Kristomun|Kristomun]] ([[User talk:Kristomun|talk]]) 00:06, 23 November 2021 (UTC)

== Clone dependence ==

Is the bit about the limited range of clone failures true? It'd seem to me that there are two types of clone failures that this could be subjected to: crowding (failing the Copeland component) and ordinary teaming inside the Smith set (failing the Borda component). For the latter, something along the lines of

{{ballots|
12: A>B>C>D>E>F
11: B>C>A>D>E>F
10: C>A>B>D>E>F
}}

The Copeland set is {A,B,C}. A and B tie for Borda score, and now the usual teaming tricks work, e.g.

{{ballots|
12: A1>A2>B>C>D>E>F
11: B>C>A1>A2>D>E>F
10: C>A1>A2>B>D>E>F
}}

and A wins. [[User:Kristomun|Kristomun]] ([[User talk:Kristomun|talk]]) 12:50, 24 November 2021 (UTC)