User:R.H./Condorcet, IRV, travel through time and dimensions
Condorcet Voting is like interdimensional travel. (like in the TV show "Sliders"). You know that Plurality Voting with only 2 candidates shows clear results that are easy to grasp so you travel to many different dimensions that are identical except that all candidates but 2 (a different pair in each dimension) are somehow missing (nudge, nudge).
Instant Runoff is like time travel (like in the "Back to the Future" movies) where those voters that vote for the least popular candidate according to Plurality are the first to get back in time to the point when voting is. However their favourite disappeared (wink, wink). That happens repeatedly until only 2 candidates are left.
Everybody knows that interdimensional travel is less dangerous than travel backwards in time, especially if you meet yourself there. This is why I prefer some Condorcet methods to Instant Runoff (and this is also why "Sliders" is more boring than "Back to the Future").
New (?) single winner method without proper name yet: Even if you prefer time travel, would it not be more fun to allow those voters that voted for the Plurality winner to be the first time travellers so they can get rid of the candidate they despise most (measured for example by the most last place ranks in the traveller group) and repeat that until one is left?
Take a look at PWVGBITAKTCTDMMBMLPRITTGRV (Plurality winner voters go back in time and kill the candidate they despise most, measured by most last place ranks in the traveller group - repeat voting):
1. situation 39 A>B>C 35 C>B>A 26 B>C>A
The A-Team goes back in time and kills C. B (Condorcet-Winner) wins.
1.b) reversal which shows that Plurality fails Reversal Symmetry. 39 C>B>A 35 A>B>C 26 A>C>B
The followers of A go back in time and kill C. A (Condorcet Winner) wins. Hmm, now I ask myself whether the travelling group should only shoot one or if it is also okay to pepper a bit the less-but-still despised in preparation of rounds to come. I will come to a conclusion after I am sure how the version without peppering works.
2. situation: a Condorcet Cycle 39 A>B>C 35 C>A>B 26 B>C>A
The A followers go back in time and kill C. A wins.
2. b) reversal which shows Instant Runoff fails Reversal Symmetry. 39 C>B>A 35 B>A>C 26 A>C>B
The C supportes go back in time and kill A. C wins.
3. situation: The second situation changes (but is still a Condorcet Cycle) so that 10 people from the B>A>C crew go to the A>B>C group which shows that Instant Runoff fails Mono-Raise. 49 A>B>C 25 C>A>B 26 B>C>A
The A group goes back in time and kills C. A wins.
3. b) reversal which shows again that Instant Runoff fails Reversal Symmetry. 49 C>B>A 25 B>A>C 26 A>C>B
The C group goes back in time and kills A. C wins.
Looks good so far. Given that this ends with a duel, the Condorcet Loser Criterion is satisfied. The First Place Majority Criterion is also satisfied. What else?
Let's try this junk:
10% FarRight>Right>Centrist>Left>FarLeft 10% Right>FarRight>Centrist>Left>FarLeft 15% Right>Centrist>FarRight>Left>FarLeft 16% Centrist>Right>Left>FarRight>FarLeft 15% Centrist>Left>Right>FarLeft>FarRight 13% Left>Centrist>FarLeft>Right>FarRight 11% Left>FarLeft>Centrist>Right>FarRight 10% FarLeft>Left>Centrist>Right>FarRight Round 1: Centrist voters travel back in time and kill FarLeft. Result: 10% FarRight>Right>Centrist>Left 10% Right>FarRight>Centrist>Left 15% Right>Centrist>FarRight>Left 16% Centrist>Right>Left>FarRight 15% Centrist>Left>Right>FarRight 13% Left>Centrist>Right>FarRight 11% Left>Centrist>Right>FarRight 10% Left>Centrist>Right>FarRight Round 2: Left voters travel back in time don't kill the centrist (his crew killed far left after all) but FarRight. 10% Right>Centrist>Left 10% Right>Centrist>Left 15% Right>Centrist>Left 16% Centrist>Right>Left 15% Centrist>Left>Right 13% Left>Centrist>Right 11% Left>Centrist>Right 10% Left>Centrist>Right Round 3: Now voters for Right have the upper hand and kill Left 10% Right>Centrist 10% Right>Centrist 15% Right>Centrist 16% Centrist>Right 15% Centrist>Right 13% Centrist>Right 11% Centrist>Right 10% Centrist>Right Round 4: Centrist wins the duel. 65% Centrist 35% Right
40 BUVWCXYZA 25 UVWCABXYZ 35 AUVWBXYZC Round 1: B kills A: 40 BUVWCXYZ 25 UVWCBXYZ 35 UVWBXYZC Round 2: U kills C: 40 BUVWXYZ 25 UVWBXYZ 35 UVWBXYZ Round 3: U kills Z: 40 BUVWXY 25 UVWBXY 35 UVWBXY Round 4: U kills Y: 40 BUVWX 25 UVWBX 35 UVWBX Round 5: U kills X: 40 BUVW 25 UVWB 35 UVWB Round 6: U kills B: 40 UVW 25 UVW 35 UVW Round 7: U kills W: 40 UV 25 UV 35 UV Round 8: U wins 100% FLAWLESS VICTORY.
Looks good the way it kills Tideman Clones. Maybe this even satisfies Mutual Majority?
Reverse:
40 AZYXCWVUB 25 ZYXBACWVU 35 CZYXBWVUA Round 1: A kills B: 40 AZYXCWVU 25 ZYXACWVU 35 CZYXWVUA Round 2: A kills U: 40 AZYXCWV 25 ZYXACWV 35 CZYXWVA Round 3: A kills V: 40 AZYXCW 25 ZYXACW 35 CZYXWA Round 4: A kills W: 40 AZYXC 25 ZYXAC 35 CZYXA Round 5: A kills C: 40 AZYX 25 ZYXA 35 ZYXA Round 6: Z kills A: 40 ZYX 25 ZYX 35 ZYX Round 7: Z kills X and then wins against Y. 100%
From Center for Range Voting puzzle page (http://math.temple.edu/~wds/crv/PuzzlePage.html)
15 people 5 A>D>F>E>C>B 4 B>E>F>D>C>A 3 C>B>E>D>F>A 2 D>C>F>A>E>B 1 E>C>F>D>B>A A wins plurality, B wins plurality plus top-2 runoff, C wins sequential runoff (IRV), D wins Borda count, E wins Condorcet, F wins Approval (assuming the top-three candidates are "approved" by each voter).
Testing with my method
5 A>D>F>E>C>B 4 B>E>F>D>C>A 3 C>B>E>D>F>A 2 D>C>F>A>E>B 1 E>C>F>D>B>A First round: The A voters go back in time and kill B: 5 A>D>F>E>C 4 E>F>D>C>A 3 C>E>D>F>A 2 D>C>F>A>E 1 E>C>F>D>A
Second round: Draw between A and E. I hadn't considered this. Possible solutions: a) The more experienced travellers go back again. If the groups in the draw travelled as often, whoever travelled first. b) The less experiended... c) random d) something else I'll take a) without any reasoning whatsoever! So
Third round: The A voters go back in time and kill C: 5 A>D>F>E 4 E>F>D>A 3 E>D>F>A 2 D>F>A>E 1 E>F>D>A Fourth round: The E voters who now have the majority of first place votes go back in time and kill A: 5 D>F>E 4 E>F>D 3 E>D>F 2 D>F>E 1 E>F>D Fifth round: The E voters go back in time and kill D: 5 F>E 4 E>F 3 E>F 2 F>E 1 E>F sixth round: E wins (Condorcet Winner!)
100 voters, 4 candidates 49 A>B>C>D 26 C>B>D>A 25 D>B>C>A First round: The A voters go back in time and kill D: 49 A>B>C 26 C>B>A 25 B>C>A Second round: The A voters go back in time and kill C: 49 A>B 26 B>A 25 B>A Third round: B wins (Condorcet Winner!)
Voting example from Wikipedia (http://en.wikipedia.org/wiki/Condorcet%27s_method):
100 voters decide between Memphis, Nashville, Knoxville, Chattanooga 42 M>N>C>K 26 N>C>K>M 15 C>K>N>M 17 K>C>N>M Round 1: The M crowd goes back in time and kills K: 42 M>N>C 26 N>C>M 15 C>N>M 17 C>N>M Round 2: M kills C: 42 M>N 26 N>M 15 N>M 17 N>M Round 3: N (Condorcet Winner!) wins.
I need to somehow solve ties.