Chicken dilemma

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The "chicken dilemma" refers to a situation where two similar candidates share a majority, but are opposed by one candidate which has a plurality against either of the two. This can happen when there is a majority split into two subfactions (below called A and B), competing against a united minority (below called C) that is bigger than either of the subfactions.

This scenario has been called the "chicken dilemma" because in many election systems, the two majority subfactions are in a situation that resembles the classic "chicken" or "snowdrift" game (especially if voters are not sure which of the two subfactions is larger).

Analysis[edit | edit source]

If we assume each faction has a single, coordinated strategy defined as "cooperate" (vote both candidates A and B above bottom) or "defect" (bullet vote, with only the favorite above bottom); and that each faction values its preferred choice at 10, its less-preferred choice at 8, and candidate C at 0, many voting systems lead to the following payoff matrix:

cooperate defect
cooperate 9, 9 8, 10
defect 10, 9 0, 0
Fig. 2: Chicken with numerical payoffs

There are various ways to deal with this situation. For instance:

  1. Some voting systems, such as approval voting, ignore the problem. Perhaps the assumption here is that it will be impossible to organize a defection without prompting a retaliation, and thus that both sides will prefer to cooperate. ("Mutual assured destruction"?)
  2. Some voting systems, such as Majority Choice Approval, try to exploit the fact that each faction is not a single coordinated entity, but a group of individual voters. The idea is that if a small number of voters defect, they should be ignored; hopefully, in that situation, majority cooperation will be a stable strategy.
  3. Other voting systems, such as ICT, try to exploit the fact that in a real-world election, A and B are never perfectly balanced; one subfaction is always larger. In this case, a voting system can encourage the smaller group to cooperate by threatening to elect C (punishing both groups) if the smaller group defects. The criterion below is passed only by this kind of voting system.

The chicken dilemma happens when there is a Condorcet winner and a majority Condorcet loser, but not a majority Condorcet winner. In many voting systems, supporters of one of the two similar candidates have a dilemma, like a game of "chicken": they can either "cooperate" and support both similar candidates, helping to ensure the opposing plurality candidate loses but risking a win by the less-preferred of the similar ones; or they can "betray" and support only their favorite candidate, trying to take advantage of cooperation by the other side.

An example of a chicken dilemma scenario, in the format of "#voters:true preferences":

  • 33: A>B>>C
  • 22: B>A>>C
  • 45: C>>A=B

Definition[edit | edit source]

Formal definition[edit | edit source]

The A voters are the voters who vote A over everyone else. The B voters are the voters who vote B over everyone else. The C voters are the voters who vote C over everyone else.Premise

  1. There are 3 candidates: A, B, and C.
  2. The A voters and the B voters, combined, add up to more than half of the voters in the election.
  3. The A voters are more numerous than the B voters. The C voters are more numerous than the A voters, and more numerous than the B voters.
  4. The A voters vote B over C. The B voters refuse to vote A over anyone.
  5. None of the C voters vote A or B over the other.

Requirement[edit | edit source]

B doesn't win.

Further analysis[edit | edit source]

In the chicken dilemma scenario described in the premise of the Chicken Dilemma Criterion (CD), defined above, if B won, then the B voters would have successfully taken advantage of the A voters' cooperativeness. The A voters wanted to vote both A and B over the candidate disliked by both the A voters and B voters. Thereby they helped {A,B} against the worse candidate. But, with methods that fail CD, the message is "You help, you lose".

Methods passing criterion[edit | edit source]

Some methods that pass the Chicken Dilemma Criterion:

ICT, Symmetrical ICT, MMPO, MDDTR, IRV, Benham's method, Woodall's method

Because CD is so simple, such a simple situation, could there be another simple implementation of it?

...maybe one that doesn't speak of numbers of voters in the factions?

CD is sufficient, as-is, but here is a non-numerical definition:

CD2:[edit | edit source]

Supporting definition:

The A voters are the voters who vote A over everyone else. The B voters are the voters who vote B over everyone else. The C voters are the voters who vote C over everyone else.

Premise:

1. There are 3 candidate: A, B, and C.

2. If the A voters and B voters all voted both A and B over C, then C couldn't win.

3. The ballot set is such that if C withdrew from the election and the count, A would win.

4. The A voters vote B over C.

5. The B voters don't vote A over anyone.

Requirement:

B doesn't win.

[end of CD2 definition]